Many students find completing past exams a valuable way to study. However, checking your working is not always easy. We provide complete solutions to several years worth of past exams for the courses listed below. The solutions are sold during the last weeks of semester 1 and 2.  We try our best to make the solutions error free, but sometimes we make mistakes.  We will put a full list of errors here as they are found (until they are corrected for the following semester).

Should you be the first person with a correctly identified and clearly explained mistake which is not purely a transcribing or numerical error (the final decision rests in the hands of the committee), AUMS will refund you the price of the exam solutions.

Listed below are the error corrections for our exam solutions. If you find any errors or require any other information, please let us know by contacting

Maths IA:

  • Q2) b) Algebra: The solution should say linearly Independent, not dependent, as \(\det A \neq 0\)

Engineering Maths IIA:

Practice Exam 1
  • Q1 a): The characteristic equation should \(t\) have \(-2\) not \(+2\).
Practice Exam 2
  • Q1 e) i) & ii): Function should be with respect to \(t\) not \(x\)

Practice Exam 3

  • Q3: \(\frac{\mathrm{d}w}{\mathrm{d}t}\) was mis-written as \(\frac{\mathrm{d}x}{\mathrm{d}t}\) (Start of page 16).

Practice Exam 4

  • Q5 b): The minus has been dropped when evaluating the integral at 0, the correct answer is \(\frac{-4\pi}{3}\).

Practice Exam 5

  • Q1 e) i) & ii): Function should be with respect to \(t\) not \(x\).
  • Q2 e): The \((-4B-C+D)\) should be \((-4B-C+2D)\), this changes the solution to \(d=\frac54\).


  • Q2 d): Due to the missing negative sign \(w = Ax\) should be \(w = \frac Ax\).
  • Q4 b): The \(\frac 2\pi\) factor for \(b_n\) (seen outside the integral expression on the left hand side of the page) was accidentally omitted later in the question.

Numerical Methods:

  • Q1 c): There is a minor typo, should be \(x_j\) not \(x_j+1\)
  • Q3 (b) \(x_1 = (1,0,2)^T\) should be \(x_1 = (1,-2,2)^T\)